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Fracture and Fatigue: How Things Actually Fail

Most catastrophic structural failures happen far below yield strength, because a crack was already there. This lesson builds the fracture mechanics that predicts the largest crack a part can carry, shows why raising strength shrinks that number, and works through the two disasters that turned fatigue from a curiosity into a design discipline.

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The number that does not predict failure

A design that keeps every stress below yield, with a factor of safety on top, feels rigorous. It is also the reason a great many structures have failed.

Pressure vessels burst at a third of yield. Axles that ran for a decade snap in normal service. A bridge that carried its design load for forty years falls down under the same load it always carried.

In all of these, the material never yielded anywhere. Something else happened: a crack existed, and a crack changes the problem entirely.

Key idea: Yield strength describes an undamaged part. Real parts contain cracks from casting porosity, weld defects, machining marks, corrosion pits or fatigue, and once a crack is present the governing quantity is not stress but stress and crack size together. Fracture mechanics is the discipline that handles the second case, and it exists because the first case was not enough.

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1. The number that does not predict failure

A design that keeps every stress below yield, with a factor of safety on top, feels rigorous. It is also the reason a great many structures have failed.

Pressure vessels burst at a third of yield. Axles that ran for a decade snap in normal service. A bridge that carried its design load for forty years falls down under the same load it always carried.

In all of these, the material never yielded anywhere. Something else happened: a crack existed, and a crack changes the problem entirely.

Key idea: Yield strength describes an undamaged part. Real parts contain cracks from casting porosity, weld defects, machining marks, corrosion pits or fatigue, and once a crack is present the governing quantity is not stress but stress and crack size together. Fracture mechanics is the discipline that handles the second case, and it exists because the first case was not enough.

2. A hole triples the stress

Stress flows through a part like a fluid, and anything it must go around crowds it. For an elliptical hole of half-length aa and tip radius ρ\rho in a wide plate, the stress at the tip is

σmax=σ(1+2aρ)\sigma_{\max} = \sigma \left(1 + 2\sqrt{\frac{a}{\rho}}\right)

A circular hole has a=ρa = \rho, giving a factor of exactly 3, regardless of how large the hole is. Make the ellipse long and sharp and the factor grows without bound; in the limit of a perfectly sharp crack the predicted stress is infinite.

In practice: This is why fillet radii matter more than most other details on a drawing, why a scratch across a glass sheet lets you snap it cleanly, and why an aircraft window is a rounded rectangle rather than a square. The design rule that follows is simple and constantly violated: never leave a sharp internal corner in a loaded part.

3. Griffith's energy argument

An infinite stress at a crack tip is not a usable prediction, so Griffith changed the question in 1920. Instead of asking what the stress is, he asked whether extending the crack releases more energy than it costs.

Growing a crack creates new surface, which costs energy proportional to the crack length. It also relaxes the material either side, releasing stored elastic energy proportional to the length squared. Below a certain size the cost wins and the crack is stable; above it the release wins and the crack runs.

σf=2Eγπa\sigma_f = \sqrt{\frac{2E\gamma}{\pi a}}

Fracture stress falls as the inverse square root of crack length. Quadruple the crack and you halve the strength.

Key idea: Fracture is not a stress being exceeded, it is an energy balance tipping over. That reframing is what made brittle failure predictable, and it explains Griffith's glass fibres: strength rose as they thinned because the largest flaw they could contain shrank.

4. The two numbers that decide it

Irwin generalised Griffith in the 1950s into the form engineers use. The severity of a crack is one number, the stress intensity factor:

K=YσπaK = Y \sigma \sqrt{\pi a}

where YY is a geometry factor near 1. Every material has a critical value KICK_{IC}, its fracture toughness, and the part fails when KK reaches it.

Rearranging gives the number that actually matters in service: the largest crack the part can carry.

ac=1π(KICYσ)2a_c = \frac{1}{\pi}\left(\frac{K_{IC}}{Y\sigma}\right)^2

MaterialKICK_{IC} (MPa m1/2^{1/2})Design stress (MPa)Critical crack
Mild steel100150141 mm
High-strength steel506002.2 mm
7075 aluminium243501.5 mm
Alumina ceramic42000.13 mm
Window glass0.7500.06 mm

Mild steel tolerates a crack you could put a hand through. Glass fails at a flaw sixty microns long, which is why glass strength is really a statement about its surface condition.

5. Why stronger is sometimes more dangerous

Predict first

You swap a mild steel component for a high-strength steel one and take advantage of the extra strength by designing to a four times higher stress. What happens to the largest crack the part can survive?

This is one of the least intuitive results in engineering, and it has a direct practical consequence: raising the design stress moves the critical flaw size below what routine inspection can find.

Gotcha: A high-strength alloy is only usable if your inspection can reliably detect flaws smaller than its critical crack size. If the smallest crack you can find is 3 mm and the part fails at 2 mm, the material is not fit for that application no matter what its strength is. Specifying the alloy and specifying the inspection regime are the same decision.

6. The same steel, brittle on a cold day

Body-centred cubic metals, which includes most structural steel, become dramatically less tough below a transition temperature. Above it a crack blunts by local plastic flow; below it, dislocation motion is too sluggish and the crack propagates by cleaving straight through grains.

The United States built roughly 2,700 Liberty ships between 1941 and 1945, welded rather than riveted so they could be assembled fast. In the cold North Atlantic a large number developed brittle fractures, reported figures vary but run to around a thousand hulls, and a few split completely in two, in some cases while lying at anchor.

Three factors combined: a steel with a transition temperature above North Atlantic sea temperature, sharp corners at hatch openings acting as stress concentrators, and continuous welded construction that gave a crack an uninterrupted path. Riveted ships had cracks too, and the seams stopped them.

In practice: Charpy impact testing across a temperature range is standard for structural steel precisely because of this, and modern specifications state a toughness requirement at the lowest expected service temperature rather than at room temperature.

7. Dying of a million small loads

Fatigue is failure under repeated loading at stresses that are individually harmless. Cyclic stress moves dislocations back and forth at the surface, roughening it into microscopic intrusions, one of which sharpens into a crack that then grows a little on every cycle.

The classic picture is the S-N curve, plotting stress amplitude against cycles to failure, and it splits materials into two camps:

Steels and some titanium alloysAluminium, copper, most non-ferrous
Below a threshold stressinfinite life: the curve goes flatno threshold: the curve keeps falling
Design consequencedesign below the endurance limit and ignore cyclesevery part has a finite life and must be retired

Key idea: Aluminium has no endurance limit. There is no stress low enough to guarantee an aluminium part survives indefinitely, which is why aircraft structures have mandatory life limits measured in flight cycles and steel bridges generally do not. This single material difference shapes an entire regulatory regime.

8. The Comet, and the test that found it

The de Havilland Comet was the first jet airliner. In January and April 1954 two broke up in flight, and the fleet was grounded.

The investigation, led by Sir Arnold Hall at the Royal Aircraft Establishment at Farnborough, took an intact airframe, G-ALYU, submerged it in a purpose-built water tank, and cycled the cabin pressure to simulate flights. After roughly 3,060 simulated cycles the fuselage tore open. Strain gauges showed stress around cutout corners far above what the design had assumed, and the failure initiated at a rivet hole near a cutout.

Gotcha: The popular version is "square passenger windows". The recovered evidence and the tank test point at a corner of an escape hatch cutout and a rivet hole rather than the passenger windows, and punched rather than drilled rivet holes contributed by leaving tiny cracks. The general lesson, that a sharp corner in a pressurised skin concentrates stress and starts a fatigue crack, is correct; the specific detail is usually misremembered.

The accident aircraft had accumulated 1,290 and 900 pressurised flights, far fewer than anyone expected to matter.

9. Estimating how long a crack takes to become fatal

Once a crack exists, its growth per cycle follows the Paris law, an empirical relation that holds across a wide range of materials:

dadN=C(ΔK)m\frac{da}{dN} = C (\Delta K)^m

with ΔK=YΔσπa\Delta K = Y \Delta\sigma \sqrt{\pi a}. Integrating gives the number of cycles from a detected flaw to the critical size.

from math import pi, sqrt

C, m, Y = 1e-11, 3.0, 1.0     # typical aluminium alloy constants
ds = 100.0                    # stress range, MPa
a, af, da, N = 0.001, 0.025, 1e-7, 0.0

while a < af:
    dK = Y * ds * sqrt(pi * a)
    N += da / (C * dK ** m)
    a += da

print(f"{N:,.0f} cycles from 1 mm to 25 mm")   # about 909,000

Growing from 1 mm to 5 mm consumes 69 percent of that life. Almost all of a fatigue life is spent while the crack is too small to find easily, and the last few millimetres go quickly.

In practice: Inspection intervals are set from this integral. The interval is chosen so that a crack just below the detection threshold at one inspection cannot reach critical size before the next, which is why the interval depends on the inspection method as much as on the structure.

10. Three ways to design against it

The field settled on three philosophies, and which one applies is a decision about consequences rather than about materials.

PhilosophyAssumptionPracticeUsed for
Infinite lifestay below the endurance limitdesign stress low, ignore cycle countsteel machinery, non-ferrous excluded
Safe lifethe part will fail eventuallytest to failure, retire at a fraction of that lifehelicopter rotor components, landing gear
Damage tolerancecracks are already presentassume the largest flaw inspection could miss, inspect on a computed intervalcommercial aircraft structure, pressure vessels

Damage tolerance is the modern default for anything whose failure is unacceptable, and it inverts the usual mindset: you do not assume the structure is sound, you assume it is cracked and prove the crack cannot get dangerous before someone looks again.

Key idea: The historical pattern in every case in this lesson is the same. The mechanism existed long before the failures, the failures made it a design requirement, and the investigation produced the analysis method. Fracture mechanics is largely a record of accidents that were expensive enough to fund the mathematics.

Check your understanding

The lesson ends with a 5-question quiz. Take it in the player above to see your score.

  1. What is the stress concentration factor at the edge of a circular hole in a wide plate under tension?
    • 1, since a circular hole is the optimal shape
    • 2
    • 3, independent of the hole's size
    • It depends on the hole diameter relative to the plate width
  2. You quadruple the design stress on a part. What happens to the critical crack size, all else equal?
    • It falls by a factor of 16, since a_c goes as the inverse square of stress
    • It falls by a factor of 4
    • It is unchanged, since crack size depends only on toughness
    • It falls by a factor of 2
  3. Why do aircraft structures carry mandatory life limits in flight cycles while steel bridges generally do not?
    • Aircraft carry higher absolute stresses
    • Aluminium has no fatigue endurance limit, so no stress guarantees indefinite life
    • Bridges are inspected more often
    • Aluminium is more prone to corrosion than steel
  4. Growing a fatigue crack from 1 mm to 5 mm used 69% of the total life to 25 mm. What does that imply for inspection?
    • Inspection is unnecessary until the crack passes 5 mm
    • Cracks grow at a constant rate, so intervals can be evenly spaced
    • Most of the usable warning time occurs while the crack is small and hardest to detect, so detection threshold sets the interval
    • Inspection should focus on the final millimetres, where growth is fastest
  5. What does damage-tolerant design assume?
    • That the structure contains no defects after manufacture
    • That stresses never exceed the endurance limit
    • That the part will be replaced before any crack initiates
    • That a crack just below the inspection detection threshold is already present

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